## Quant Question Of The Day: 267

**Geometry**

**The angle bisectors BD and CE of a triangle ABC are divided by the incentre I in the ratios 3 : 2 and 2 : 1 respectively. Then the ratio in which I divides the angle bisector through A is-(A) 3 : 1 (B) 11 : 4 (C) 6 : 5 (D) 7 : 4**

**See our previous ‘Questions of the Day’:**

Quant Question Of The Day: 266

Quant Question Of The Day: 265

Quant Question Of The Day: 264

3:1

11:4

11:4

11:4